Undergraduate

Now we can consider the limit of ln ( y ) . lim x ln ( y ) = lim x 6 x ln 1

Now we can consider the limit of
ln(y).
limxln(y)=limx6x ln
1+
3x
=limx
ln
1+
3x
16x
These limits are indeterminant forms, so we can apply L'Hospital's Rule as follows.
limx
ln
1+
3x
16x
L'H=
limx
11+
3x
16x2

Step by Step Solution

1 Understanding Responsive Design Principles

blur-text-image

Related Multivariable Calculus Questions