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Multivariable Calculus
Now we can consider the limit of ln ( y ) .
Undergraduate
Now we can consider the limit of ln ( y ) . lim x ln ( y ) = lim x 6 x ln 1
Now we can consider the limit of
ln
(
y
)
.
lim
x
ln
(
y
)
=
lim
x
6
x ln
1
+
3
x
=
lim
x
ln
1
+
3
x
1
6
x
These limits are indeterminant forms, so we can apply L'Hospital's Rule as follows.
lim
x
ln
1
+
3
x
1
6
x
L
'
H
=
lim
x
1
1
+
3
x
1
6
x
2
Step by Step Solution
1
Understanding Responsive Design Principles
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EXAMPLE 6 Evaluate lim x 0 e 5 / x . SOLUTION If we let t = 5 / x , we know that t as x 0 . Therefore, by lim x ex = 0 , lim x 0 e 5 / x = lim t et = . ( See this exercise. )
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