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Evaluate Integral from Upper C to left parenthesis x plus y right parenthesis ds C ( x + y ) ds where C is the

Evaluate
Integral from Upper C to left parenthesis x plus y right parenthesis dsC(x+y)ds
where C is the straight-line segment
x equals tx=t,
y equals left parenthesis 1 minus t right parenthesisy=(1t),
z equals 0z=0
from
left parenthesis 0 comma 1 comma 0 right parenthesis(0,1,0)
to
left parenthesis 1 comma 0 comma 0 right parenthesis(1,0,0).

Step by Step Solution

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