Find dydx by implicit differentiation.
x ln y plus y equals x Superscript Baseline y Superscript xlnyyxy
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Part
AStartFraction dy Over dx EndFraction equals StartFraction x Superscript Baseline y Superscript Baseline minus ln y Over x minus x Superscript Baseline y Superscript Baseline plus EndFraction
StartFraction dy Over dx EndFraction equals StartFraction x Superscript Baseline y Superscript Baseline minus ln y Over x minus x Superscript Baseline y Superscript Baseline plus EndFractiondydxxylnyxxy
BStartFraction dy Over dx EndFraction equals StartFraction x Superscript Baseline y Superscript Baseline minus ln y Over x minus x Superscript Baseline y Superscript Baseline plus y EndFraction
StartFraction dy Over dx EndFraction equals StartFraction x Superscript Baseline y Superscript Baseline minus ln y Over x minus x Superscript Baseline y Superscript Baseline plus y EndFractiondydxxylnyxxyy
CStartFraction dy Over dx EndFraction equals StartFraction x Superscript Baseline y Superscript Baseline minus y ln y minus Over x minus x Superscript Baseline y Superscript Baseline plus y EndFraction
StartFraction dy Over dx EndFraction equals StartFraction x Superscript Baseline y Superscript Baseline minus y ln y minus Over x minus x Superscript Baseline y Superscript Baseline plus y EndFractiondydxxyylnyxxyy
DStartFraction dy Over dx EndFraction equals StartFraction x Superscript Baseline y Superscript Baseline minus y ln y Over x minus x Superscript Baseline y Superscript Baseline plus y EndFraction
StartFraction dy Over dx EndFraction equals StartFraction x Superscript Baseline y Superscript Baseline minus y ln y Over x minus x Superscript Baseline y Superscript Baseline plus y EndFraction