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Calculus
Calculus Of Variations
Solve the separable differential equation 5 x 8 y ( x 2
Undergraduate
Solve the separable differential equation 5 x 8 y ( x 2 + 1 ) ^ 1 / 2 dydx = 0 . Subject to
Solve the separable differential equation
5
x
8
y
(
x
2
+
1
)
^
1
/
2
dydx
=
0
.
Subject to the initial condition: y
(
0
)
=
4
.
y
=
Step by Step Solution
1
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Find dydx . x = t 8 + t , y = 8 + t dydx = ( 8 + t ) 2 8 dydx . x = t 8 + t , y = 8 + t dydx = ( 8 + t ) 2 8
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