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Undergraduate
Calculus
Calculus Of Variations
iii ) Complete the following table for Q = 1 5 and
Undergraduate
iii ) Complete the following table for Q = 1 5 and Q = 2 5 . table [ [ K , L ,
iii
)
Complete the following table for
Q
=
1
5
and
Q
=
2
5
.
\
table
[
[
K
,
L
,
]
,
[
1
0
,
0
,
Q
]
,
[
1
0
,
5
,
1
5
]
,
[
5
,
1
0
,
1
5
]
,
[
2
5
,
1
5
,
1
5
1
5
P
=
[
2
5
q
(
1
-
q
^
2
)
^
0
.
5
find the defiviative usingchain rule
Step by Step Solution
1
Understanding Responsive Design Principles
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Chain Rule ( Multiple independent variables ) Let z ( x , y ) = - 3 x 2 - 5 y 2 where x = 4 s - 7 tChain Rule ( Multiple independent variables ) Let z ( x , y ) = - 3 x 2 - 5 y 2 where x = 4 s - 7 t
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