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( 1 ) Let C 1 and C 2 be arbitrary constants. The general solution to the homogeneous differential equation 3 6 1 x 2

(1) Let C1 and C2 be arbitrary constants. The general solution to the homogeneous differential equation 361x2y''285xy'4y=0 is the function y(x)=C1y1(x)C2y2(x)=C1
C2
(2) The unique solution to the initial value problem
361x2y''285xy'4y=0,y(1)=3,y'(1)=4
is the function y(x)= for xin
For - type -inf and for type inf.
( 1 ) Let C 1 and C 2 be arbitrary constants. The

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