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Solve the following word problem. Money is invested at two rates of interest. One rate is 6 % 6 % and the other is 4

Solve the following word problem.
Money is invested at two rates of interest. One rate is 6%6% and the other is 4%4%. If there is $1000$1000 more invested at 6%6% than at 4%4%, find the amount invested at each rate if the total annual interest received is $860$860. Let x=x= amount invested at 6%6% and y=y= amount invested at 4%4%. Then the system that models the problem is {x=y+10000.06x+0.04y=860{x=y+10000.06x+0.04y=860. Solve the system by using the method of addition.

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