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Find all real numbers that satisfy the equation . 2 sine left parenthesis 5 x right parenthesis 2 sin ( 5 x ) minus 1

Find all real numbers that satisfy the equation.2 sine left parenthesis 5 x right parenthesis2sin(5x)minus11equals=0Question content area bottomPart 1Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice.A.The solution set is StartSet x font size decreased by 6| font size decreased by 6 x equals nothing plus 2 k pi EndSetx | x= enter your response here 2k, where k is any integer.(Use angle measures greater than or equal to 0 and less than 2pi. Round the final answer to the nearest hundredth as needed. Round all intermediate values to the nearest thousandth as needed.)B.The solution set is StartSet x font size decreased by 6| font size decreased by 6 x equals nothing plus StartFraction 2 k pi Over 5 EndFraction or x equals nothing plus StartFraction 2 k pi Over 5 EndFraction EndSetx | x= enter your response here 2k5 or x= enter your response here 2k5, where k is any integer.(Use angle measures greater than or equal to 0 and less than StartFraction 2 pi Over 5 EndFraction25. Use ascending order. Round the final answer to the nearest hundredth as needed. Round all intermediate values to the nearest thousandth as needed.)C.The solution set is StartSet x font size decreased by 6| font size decreased by 6 x equals nothing plus StartFraction 2 k pi Over 5 EndFraction EndSetx | x= enter your response here 2k5, where k is any integer.(Use angle measures greater than or equal to 0 and less than StartFraction 2 pi Over 5 EndFraction25. Round the final answer to the nearest hundredth as needed. Round all intermediate values to the nearest thousandth as needed.)D.The solution set is StartSet x font size decreased by 6| font size decreased by 6 x equals nothing plus 2 k pi or x equals nothing plus 2 k pi EndSetx | x= enter your response here 2k or x= enter your response here 2k, where k is any integer.(Use angle measures greater than or equal to 0 and less than 2pi. Use ascending order. Round the final answer to the nearest hundredth as needed. Round all intermediate values to the nearest thousandth as needed.)E.There is no solution.

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